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remove Symbol::empty

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the only use of this function is to determine whether a lambda has a non-set
formal, but this use is arguably better served by Symbol::set and using a
non-Symbol instead of an empty symbol in the parser when no such formal is present.
This commit is contained in:
pennae 2022-03-05 14:20:25 +01:00
parent 90b5c0a1a6
commit ff0fd91ed2
5 changed files with 8 additions and 13 deletions
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2
src/libexpr/value-to-xml.cc
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@ -139,7 +139,7 @@ static void printValueAsXML(EvalState & state, bool strict, bool location,
if (v.lambda.fun->hasFormals()) {
XMLAttrs attrs;
if (!v.lambda.fun->arg.empty()) attrs["name"] = v.lambda.fun->arg;
if (v.lambda.fun->arg.set()) attrs["name"] = v.lambda.fun->arg;
if (v.lambda.fun->formals->ellipsis) attrs["ellipsis"] = "1";
XMLOpenElement _(doc, "attrspat", attrs);
for (auto & i : v.lambda.fun->formals->lexicographicOrder())