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remove Symbol::empty

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the only use of this function is to determine whether a lambda has a non-set
formal, but this use is arguably better served by Symbol::set and using a
non-Symbol instead of an empty symbol in the parser when no such formal is present.
This commit is contained in:
pennae 2022-03-05 14:20:25 +01:00
parent 90b5c0a1a6
commit ff0fd91ed2
5 changed files with 8 additions and 13 deletions
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4
src/libexpr/eval.cc
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@ -1342,7 +1342,7 @@ void EvalState::callFunction(Value & fun, size_t nrArgs, Value * * args, Value &
ExprLambda & lambda(*vCur.lambda.fun);
auto size =
(lambda.arg.empty() ? 0 : 1) +
(!lambda.arg.set() ? 0 : 1) +
(lambda.hasFormals() ? lambda.formals->formals.size() : 0);
Env & env2(allocEnv(size));
env2.up = vCur.lambda.env;
@ -1355,7 +1355,7 @@ void EvalState::callFunction(Value & fun, size_t nrArgs, Value * * args, Value &
else {
forceAttrs(*args[0], pos);
if (!lambda.arg.empty())
if (lambda.arg.set())
env2.values[displ++] = args[0];
/* For each formal argument, get the actual argument. If