ParsedURL: Remove url field

This prevents a 'url' field that is out of sync with the other
fields. You can use to_string() to get the full URL.

src/libutil/url.cc

@@ -40,7 +40,6 @@ ParsedURL parseURL(const std::string & url)
             path = "/";
 
         return ParsedURL{
-            .url = url,
             .base = base,
             .scheme = scheme,
             .authority = authority,
@@ -136,6 +135,12 @@ std::string ParsedURL::to_string() const
         + (fragment.empty() ? "" : "#" + percentEncode(fragment));
 }
 
+std::ostream & operator << (std::ostream & os, const ParsedURL & url)
+{
+    os << url.to_string();
+    return os;
+}
+
 bool ParsedURL::operator ==(const ParsedURL & other) const noexcept
 {
     return