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Generalize DerivationType in preparation for impure derivations

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This commit is contained in:
John Ericson 2022-03-18 00:36:52 +00:00
parent 049fae155a
commit a544ed7684
9 changed files with 148 additions and 95 deletions
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62
src/libstore/derivations.hh
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@ -85,30 +85,50 @@ typedef std::map<std::string, std::pair<DerivationOutput, std::optional<StorePat
output IDs we are interested in. */
typedef std::map<StorePath, StringSet> DerivationInputs;
enum struct DerivationType : uint8_t {
InputAddressed,
DeferredInputAddressed,
CAFixed,
CAFloating,
struct DerivationType_InputAddressed {
bool deferred;
};
/* Do the outputs of the derivation have paths calculated from their content,
or from the derivation itself? */
bool derivationIsCA(DerivationType);
struct DerivationType_ContentAddressed {
bool pure;
bool fixed;
};
/* Is the content of the outputs fixed a-priori via a hash? Never true for
non-CA derivations. */
bool derivationIsFixed(DerivationType);
typedef std::variant<
DerivationType_InputAddressed,
DerivationType_ContentAddressed
> _DerivationTypeRaw;
/* Is the derivation impure and needs to access non-deterministic resources, or
pure and can be sandboxed? Note that whether or not we actually sandbox the
derivation is controlled separately. Never true for non-CA derivations. */
bool derivationIsImpure(DerivationType);
struct DerivationType : _DerivationTypeRaw {
using Raw = _DerivationTypeRaw;
using Raw::Raw;
using InputAddressed = DerivationType_InputAddressed;
using ContentAddressed = DerivationType_ContentAddressed;
/* Does the derivation knows its own output paths?
* Only true when there's no floating-ca derivation involved in the closure.
*/
bool derivationHasKnownOutputPaths(DerivationType);
/* Do the outputs of the derivation have paths calculated from their content,
or from the derivation itself? */
bool isCA() const;
/* Is the content of the outputs fixed a-priori via a hash? Never true for
non-CA derivations. */
bool isFixed() const;
/* Is the derivation impure and needs to access non-deterministic resources, or
pure and can be sandboxed? Note that whether or not we actually sandbox the
derivation is controlled separately. Never true for non-CA derivations. */
bool isImpure() const;
/* Does the derivation knows its own output paths?
Only true when there's no floating-ca derivation involved in the
closure, or if fixed output.
*/
bool hasKnownOutputPaths() const;
inline const Raw & raw() const {
return static_cast<const Raw &>(*this);
}
};
struct BasicDerivation
{
@ -189,11 +209,11 @@ typedef std::map<std::string, Hash> CaOutputHashes;
struct DrvHash {
Hash hash;
enum struct Kind {
enum struct Kind: bool {
// Statically determined derivations.
// This hash will be directly used to compute the output paths
Regular,
// Floating-output derivations (and their dependencies).
// Floating-output derivations (and their reverse dependencies).
Deferred,
};