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function-trace: always show the trace

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If the user invokes nix with --trace-function-calls it means that they
want to see the trace.
This commit is contained in:
zimbatm 2019-09-18 11:40:11 +00:00
parent c6a0f4c393
commit 619cc4af85
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GPG key ID: 71BAF6D40C1D63D7
3 changed files with 4 additions and 6 deletions
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4
src/libexpr/function-trace.hh
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@ -12,13 +12,13 @@ struct FunctionCallTrace
FunctionCallTrace(const Pos & pos) : pos(pos) {
auto duration = std::chrono::high_resolution_clock::now().time_since_epoch();
auto ns = std::chrono::duration_cast<std::chrono::nanoseconds>(duration);
vomit("function-trace entered %1% at %2%", pos, ns.count());
printMsg(lvlInfo, "function-trace entered %1% at %2%", pos, ns.count());
}
~FunctionCallTrace() {
auto duration = std::chrono::high_resolution_clock::now().time_since_epoch();
auto ns = std::chrono::duration_cast<std::chrono::nanoseconds>(duration);
vomit("function-trace exited %1% at %2%", pos, ns.count());
printMsg(lvlInfo, "function-trace exited %1% at %2%", pos, ns.count());
}
};
}